There s two green marbles in the bag.
There are r red marbles blue marbles in a bag.
So this is all the possible outcomes.
P red ask for details.
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And then there s one blue marble in the bag.
In order to reduce the number of variables to two and limit the number of equations in the system to two we can subsitute b r 88 into r b t so that it becomes r r 88 t and then becomes 2r 88 t.
How many marbles total are in the bag.
There is an equal number of red and blue marbles h0 or.
One of two conditions exists with respect to the number of red and blue marbles.
These are clearly all yellow.
There s one blue marble.
There are 20 blue marbles in the bag.
You reach in and randomly draw a marble replace it and draw another marble.
There are 5 red marbles 15 blue marbles and 5 green marbles in a bag.
There are 5 red marbles 7 green marbles 4 black marbles and 8 blue marbles in a bag suppose you select one marble at random.
Each marble is either red or blue.
So i could pick that green marble or that green marble.
A bag of marbles consists entirely of red blue and green marbles.
The ratio of red to blue to green marbles in the bag is 2 5 7.
There are 6 red marbles 8 blue marbles and 11 green marbles in a bag what is the probability that you will randomly draw either a red or blue marble 12002178.
There s two red marbles in the bag.
So i could pick that red marble or that red marble.
Find each probability a.
Finally since there are only red and blue marbles in the bag we can say that r b t.